counting_bits
1# @leet start 2class Solution: 3 def countBits(self, n: int) -> list[int]: 4 """ 5 This question asks for the count of all bits in a range from 0 <= n. 6 To count the bits using an intrinsic, we can use integer.bit_count 7 but I manually wrote an implementation and used it. 8 The `n &= n - 1` trick counts the bits by always removing the last 9 set bit. 10 """ 11 12 def bit_count(n: int) -> int: 13 count = 0 14 while n: 15 count += 1 16 n &= n - 1 17 return count 18 19 return [bit_count(x) for x in range(n + 1)] 20 21 22# @leet end 23q = Solution().countBits 24 25 26def test(): 27 assert q(2) == [0, 1, 1] 28 assert q(5) == [0, 1, 1, 2, 1, 2]
class
Solution:
3class Solution: 4 def countBits(self, n: int) -> list[int]: 5 """ 6 This question asks for the count of all bits in a range from 0 <= n. 7 To count the bits using an intrinsic, we can use integer.bit_count 8 but I manually wrote an implementation and used it. 9 The `n &= n - 1` trick counts the bits by always removing the last 10 set bit. 11 """ 12 13 def bit_count(n: int) -> int: 14 count = 0 15 while n: 16 count += 1 17 n &= n - 1 18 return count 19 20 return [bit_count(x) for x in range(n + 1)]
def
countBits(self, n: int) -> list[int]:
4 def countBits(self, n: int) -> list[int]: 5 """ 6 This question asks for the count of all bits in a range from 0 <= n. 7 To count the bits using an intrinsic, we can use integer.bit_count 8 but I manually wrote an implementation and used it. 9 The `n &= n - 1` trick counts the bits by always removing the last 10 set bit. 11 """ 12 13 def bit_count(n: int) -> int: 14 count = 0 15 while n: 16 count += 1 17 n &= n - 1 18 return count 19 20 return [bit_count(x) for x in range(n + 1)]
This question asks for the count of all bits in a range from 0 <= n.
To count the bits using an intrinsic, we can use integer.bit_count
but I manually wrote an implementation and used it.
The n &= n - 1 trick counts the bits by always removing the last
set bit.
def
q(n: int) -> list[int]:
4 def countBits(self, n: int) -> list[int]: 5 """ 6 This question asks for the count of all bits in a range from 0 <= n. 7 To count the bits using an intrinsic, we can use integer.bit_count 8 but I manually wrote an implementation and used it. 9 The `n &= n - 1` trick counts the bits by always removing the last 10 set bit. 11 """ 12 13 def bit_count(n: int) -> int: 14 count = 0 15 while n: 16 count += 1 17 n &= n - 1 18 return count 19 20 return [bit_count(x) for x in range(n + 1)]
This question asks for the count of all bits in a range from 0 <= n.
To count the bits using an intrinsic, we can use integer.bit_count
but I manually wrote an implementation and used it.
The n &= n - 1 trick counts the bits by always removing the last
set bit.
def
test():